#include <bits/stdc++.h>
using namespace std;
struct tree{
int l,r;
char v;
}t[300];
void f(int x){
if(x==(int)'*')return;
cout<<t[x].v;
f(t[x].l);
f(t[x].r);
}
int main() {
int n;cin>>n;
char a,b,c,flag;
for(int i=1;i<=n;i++){
cin>>a>>b>>c;if(i==1)flag=(int)a;
int j=(int)a;
t[j].l=(int)b;
t[j].r=(int)c;
t[j].v=(char)a;
}
f(flag);
return 0;
}
就是简单树的建立和遍历，该题注意int和char类型转换和边界为‘*’即可
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